In [1]:
#There are four collection data types in the Python programming language:

#LIST
#It is a collection which is ordered and mutable(changeable) which Allows duplicate members.

#TUPLES
#It is a collection which is ordered and unmutable(unchangeable) which Allows duplicate members.

#SETS
#It is a collection which is unordered and unindexed which doesn't Allow duplicate members.

#DICTIONARY
#It is a collection which is unordered, changeable and indexed which doesn't Allow duplicate mem
In [2]:
#courses is list containing elements history, physics, maths and english
courses =['History' , 'Physics' , 'Maths', 'English']
courses2 = ['Art', 'Education']
In [3]:
#this will print the whole list
print(courses)

['History', 'Physics', 'Maths', 'English']
In [4]:
#you can access any element of list using index number which begins from 0.
#to print maths which is at index 2, simply write list[index_no]
print(courses[2])

Maths
In [5]:
#insert method is used add element at given index
#in this courses2 list is added to courses list at index 0.
courses.insert(0, courses2)
In [7]:
#list gets appended inside list. to avoid this we can use extend method.
print(courses)

[['Art', 'Education'], 'History', 'Physics', 'Maths', 'English']
In [8]:
#extend is used so list wont get appended inside list
courses =['History' , 'Physics' , 'Maths', 'English']
courses.extend(courses2)
In [9]:
#new list
print(courses)

['History', 'Physics', 'Maths', 'English', 'Art', 'Education']
In [10]:
#pop() removes last item and we can store it in a variable
popped= courses.pop()
print(popped)

Education
In [11]:
#reverse the order using reverse method
courses.reverse()
print(courses)

['Art', 'English', 'Maths', 'Physics', 'History']
In [12]:
#sort the list in desc order when reverse is true
courses.sort(reverse=True)
print(courses)

['Physics', 'Maths', 'History', 'English', 'Art']
In [14]:
#sorted version of list is not reflected in original list
print(sorted(courses))
#order remains same as it was before using sorted method
print(courses)

['Art', 'English', 'History', 'Maths', 'Physics']
['Physics', 'Maths', 'History', 'English', 'Art']
In [15]:
#finding index
print(courses.index('Maths'))

1
In [16]:
#finding element in list, True if there and False is not
print('English' in courses)

True
In [17]:
#Printing each element of list
for course in courses:
    print(course)

Physics
Maths
History
English
Art
In [18]:
#Printing each element with index
for index, course in enumerate(courses, start=1): 
#as start=1, index will be start from 1, default is 0
    print(index,course)

1 Physics
2 Maths
3 History
4 English
5 Art
In [19]:
#Making String from list
course_str = ', '.join(courses)
print(course_str)

Physics, Maths, History, English, Art
In [20]:
#Making List from String
new_list= course_str.split(', ')
print(new_list)

['Physics', 'Maths', 'History', 'English', 'Art']
In [21]:
#Set
cs_courses={'Maths', 'Physics', 'English', 'Sports','Chemistry' }
art_courses={'Maths', 'Art', 'English', 'Sports','Hindi' }
In [22]:
#Common in both the sets
print(cs_courses.intersection(art_courses))

{'Sports', 'Maths', 'English'}
In [23]:
#Element in set1 but not in set2
print(cs_courses.difference(art_courses))

{'Chemistry', 'Physics'}
In [24]:
#All Elements combined from both the set
print(cs_courses.union(art_courses))

{'Art', 'Chemistry', 'Hindi', 'English', 'Physics', 'Sports', 'Maths'}
In [25]:
#Creating empty list, tuple, set, dictionary
#Empty list
empty_list = []
empty_list = list()

#Empty Tuple
empty_tuple = ()
empty_tuple = tuple()

#Empty Set
empty_set = {} #this is wrong, this will create empty dictionary
empty_set = set()